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Microsoft 070-457 Exam Syllabus Topics:

Microsoft Transition Your MCTS on SQL Server 2008 to MCSA: SQL Server 2012, Part 1 Sample Questions:

1. You administer a Microsoft SQL Server 2012 database. Your database is experiencing deadlock issues. You need to be able to monitor deadlocks. Which three actions should you perform in sequence? (To answer, move the appropriate actions from the list of actions to the answer area and arrange them in the correct order.)
Build List and Reorder:

2. You use Microsoft SQL Server 2012 database to develop a shopping cart application. You need to rotate the unique values of the ProductName field of a table-valued expression into multiple columns in the output. Which Transact-SQL operator should you use?

A) UNPIVOT
B) CROSS APPLY
C) CROSS JOIN
D) PIVOT

3. You have a database that contains the tables shown in the exhibit. (Click the Exhibit button).

You need to create a query for a report. The query must meet the following requirements:
NOT use object delimiters.
Return the most recent orders first.
Use the first initial of the table as an alias.
Return the most recent order date for each customer.
Retrieve the last name of the person who placed the order.
Return the order date in a column named MostRecentOrderDate that appears as the last column in the report.
The solution must support the ANSI SQL-99 standard.
Which code segment should you use?
To answer, type the correct code in the answer area.

A) SELECT c.CustomerID --optional c.LastName, max(o.OrderDate) 'MostRecentOrderDate' FROM Customer c LEFT OUTER JOIN Orders o ON o.CustomerID = c.CustomerID GROUP BY c.CustomerID, c.LastName ORDER BY 3 DESC
B) SELECT LastName, O.OrderDate AS MostRecentOrderDate FROM Customers AS C INNER JOIN Orders AS O ON CustomerID = O.CustomerID ORDER BY O.OrderDate DESC
C) select C.Lastname, P.MostRecentOrderDate from customers AS C inner join ( select customID, MostRecentOrderDate=max(orderDate) from orders group by customID
)P
on C.customerID=P.CustomerID
order by P.MostRecentOrderDate desc

4. You administer a Microsoft SQL Server 2012 instance that contains a financial database hosted on a storage area network (SAN). The financial database has the following characteristics:
A data file of 2 terabytes is located on a dedicated LUN (drive D).
A transaction log of 10 GB is located on a dedicated LUN (drive E).
Drive D has 1 terabyte of free disk space.
Drive E has 5 GB of free disk space.
The database is continually modified by users during business hours from Monday through Friday between
09:00
hours and 17:00 hours. Five percent of the existing data is modified each day. The Finance department loads large CSV files into a number of tables each business day at 11:15 hours and 15:15 hours by using the BCP or BULK INSERT commands. Each data load adds 3 GB of data to the database. These data load operations must occur in the minimum amount of time. A full database backup is performed every Sunday at 10:00 hours. Backup operations will be performed every two hours (11:00, 13:00, 15:00, and 17:00) during business hours. You need to ensure that the backup size is as small as possible. Which backup should you perform every two hours?

A) STANDBY
B) SIMPLE
C) CHECKSUM
D) COPY_ONLY
E) BULK_LOGGED
F) FULL
G) DBO.ONLY
H) SKIP
I) RESTART
J) Transaction log
K) NORECOVERY
L) CONTINUE_AFTER_ERROR
M) NO_CHECKSUM
N) Differential

5. You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects. You need to retrieve the students who scored the highest marks for each subject along with the marks. Which Transact-SQL query should you use?

A) SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
B) SELECT Id, Name, Marks, DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank FROM StudentMarks
C) SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D) SELECT StudentCode as Code, DENSE_RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
E) SELECT StudentCode as Code, RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
F) SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G) SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H) SELECT StudentCode as Code, NTILE(2) OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode

Solutions: